Concordium CCD: 아마
Concordium은 11월 27일 13:30 UTC에 AMA를 개최합니다. 이 행사에는 Concordium의 CTO 및 CPO, CEO인 Marinus Kreuze, Ciphers.me의 제품 책임자인 Patrick Terranea가 참석합니다.
이밴트: 2023년 11월 27일 13:30 UTC
AMA가 무엇인가요?
AMA는 'Ask Me Anything'의 약자로 말 그대로 무엇이든 물어보라는 의미를 가지고 있습니다. AMA는 정식 용어는 아니지만 ICO나 Pre-sale 전 각종 커뮤니티에서 쉽게 볼 수 있는 용어입니다.
Join Our Exclusive Concordium x https://ciphers.me/en/ Live Event!
📆 November 27th at 2:30 PM CET
We are happy to invite you for a live event featuring Nibras Stiebar-Bang our CTO & CPO, Marinus Kreuze CEO & Patrick Terranea Head of Product from https://ciphers.me/en/.
https://ciphers.me/en/ are building bridges between real-world assets and NFTs on the Concordium blockchain.
What you can expect:
🌐 An introduction of https://ciphers.me/en/´
💡Exclusive insights and an exclusive demo
💬 A Q&A
Have questions? This event is your chance to interact directly with the pioneers in this space. Prepare your questions and get ready for an engaging session.
Follow the link to have an overview of our events: https://www.concordium.com/live?utm_source=Chipjers.me+AMA+on+LinkedIn&utm_medium=LinkedIn&utm_campaign=Chipjers.me+AMA+on+LinkedIn&utm_id=Ciphers.me+AMA
📆 November 27th at 2:30 PM CET
We are happy to invite you for a live event featuring Nibras Stiebar-Bang our CTO & CPO, Marinus Kreuze CEO & Patrick Terranea Head of Product from https://ciphers.me/en/.
https://ciphers.me/en/ are building bridges between real-world assets and NFTs on the Concordium blockchain.
What you can expect:
🌐 An introduction of https://ciphers.me/en/´
💡Exclusive insights and an exclusive demo
💬 A Q&A
Have questions? This event is your chance to interact directly with the pioneers in this space. Prepare your questions and get ready for an engaging session.
Follow the link to have an overview of our events: https://www.concordium.com/live?utm_source=Chipjers.me+AMA+on+LinkedIn&utm_medium=LinkedIn&utm_campaign=Chipjers.me+AMA+on+LinkedIn&utm_id=Ciphers.me+AMA
이벤트 발표 후 CCD 가격 변동
0.99%
1 일
1.60%
2 일
37.36%
지금 (1 년전에 추가됨)
이벤트가 곧 시작됩니다
0
D
0
H
0
M
0
S
✕
✕